python实现三维拟合

发布时间：2019-09-22 07:49:53编辑：auto阅读（1794）

    from  matplotlib import pyplot as plt
import  numpy as np
from mpl_toolkits.mplot3d import Axes3D

fig = plt.figure()
ax = Axes3D(fig)

#列出实验数据
point=[[2,3,48],[4,5,50],[5,7,51],[8,9,55],[9,12,56]]
plt.xlabel("X1")
plt.ylabel("X2")

#表示矩阵中的值
ISum = 0.0
X1Sum = 0.0
X2Sum = 0.0
X1_2Sum = 0.0
X1X2Sum = 0.0
X2_2Sum = 0.0
YSum = 0.0
X1YSum = 0.0
X2YSum = 0.0

#在图中显示各点的位置
for i in range(0,len(point)):

    x1i=point[i][0]
    x2i=point[i][1]
    yi=point[i][2]
    ax.scatter(x1i, x2i, yi, color="red")
    show_point = "["+ str(x1i) +","+ str(x2i)+","+str(yi) + "]"
    ax.text(x1i,x2i,yi,show_point)

    ISum = ISum+1
    X1Sum = X1Sum+x1i
    X2Sum = X2Sum+x2i
    X1_2Sum = X1_2Sum+x1i**2
    X1X2Sum = X1X2Sum+x1i*x2i
    X2_2Sum = X2_2Sum+x2i**2
    YSum = YSum+yi
    X1YSum = X1YSum+x1i*yi
    X2YSum = X2YSum+x2i*yi

# 进行矩阵运算
# _mat1 设为 mat1 的逆矩阵
m1=[[ISum,X1Sum,X2Sum],[X1Sum,X1_2Sum,X1X2Sum],[X2Sum,X1X2Sum,X2_2Sum]]
mat1 = np.matrix(m1)
m2=[[YSum],[X1YSum],[X2YSum]]
mat2 = np.matrix(m2)
_mat1 =mat1.getI()
mat3 = _mat1*mat2

# 用list来提取矩阵数据
m3=mat3.tolist()
a0 = m3[0][0]
a1 = m3[1][0]
a2 = m3[2][0]

# 绘制回归线
x1 = np.linspace(0,9)
x2 = np.linspace(0,12)
y = a0+a1*x1+a2*x2
ax.plot(x1,x2,y)
show_line = "y="+str(a0)+"+"+str(a1)+"x1"+"+"+str(a2)+"x2"
plt.title(show_line)
plt.show()

关键字：

上一篇： python + fiddler抓包测试

下一篇： Python——按键操作、时间等待、点击