python编写登录接口

发布时间:2019-05-02 06:56:58编辑:auto阅读(2477)

    要求: 输入用户名密码

          认证成功显示欢迎信息

       输错三次以后锁定

    代码如下:

    # Author:YK
    while(True):
    select=input('请问是注册还是登录')
    if select == '注册':
    register='' #将需要保存的user和password放在register中
    username = input('please input your count...')
    password = input('please input your password...')
    register=register+username+','+password+'\n'
    file1 = open('D:\\study\\code\\study_teach\\day1\\save_user.txt', 'a+',encoding='utf-8')
    #打开保存用户名和密码的文件
    file1.write(register) #写入文件
    file1.close()


    elif select == '登录':
    username = input('please input your count...')
    file2 = open('D:\\study\\code\\study_teach\\day1\\lock.txt', 'r', encoding='utf-8')
    #打开被锁定用户的文件
    count=0
    number=len(file2.readlines()) #获取文件行数
    file2.seek(0, 0) #将鼠标移动到首个字节
    while(count<number):
    count=count+1
    lines = file2.readline().strip('\n') #获取每一行的用户名字符串
    if lines == username: #判断输入的用户名是否和存储的用户名相等
    print('Your count {name} locked'.format(name=username))
    file2.close()
    exit()


    file1 = open('D:\\study\\code\\study_teach\\day1\\save_user.txt', 'r',encoding='utf-8')
    #打开保存用户名和密码的文件
    for i in range(3): #有3次机会输入密码的循环
    password = input('please input your password...')
    count = 0
    number = len(file1.readlines()) #获取文件行数
    file1.seek(0,0)
    while (count < number):
    count=count+1
    line=file1.readline().strip('\n').split(',')
    if line[0] == username and line[1] == password:
    print('Welcom to you submit') #登录成功
    exit() #退出
    if i == 2: #3次均输入错误
    file2 = open('D:\\study\\code\\study_teach\\day1\\lock.txt', 'a+',encoding='utf-8')
    file2.write(username+'\n') #将被锁定的用户名写入被锁文件当中
    file1.close()
    file2.close()
    print('Your count {name} locked'.format(name=username))
    exit()
    else:
    print('输入有错误,请重新输入')




关键字